x^2=(x+1)(x-1)

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Solution for x^2=(x+1)(x-1) equation:


Simplifying
x2 = (x + 1)(x + -1)

Reorder the terms:
x2 = (1 + x)(x + -1)

Reorder the terms:
x2 = (1 + x)(-1 + x)

Multiply (1 + x) * (-1 + x)
x2 = (1(-1 + x) + x(-1 + x))
x2 = ((-1 * 1 + x * 1) + x(-1 + x))
x2 = ((-1 + 1x) + x(-1 + x))
x2 = (-1 + 1x + (-1 * x + x * x))
x2 = (-1 + 1x + (-1x + x2))

Combine like terms: 1x + -1x = 0
x2 = (-1 + 0 + x2)
x2 = (-1 + x2)

Add '-1x2' to each side of the equation.
x2 + -1x2 = -1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = -1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = -1 + 0
0 = -1

Solving
0 = -1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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